Optimal. Leaf size=294 \[ \frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {\sqrt [3]{a} \left (b^{4/3} d+\sqrt [3]{a} b e-a \sqrt [3]{b} g-a^{4/3} h\right ) \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} b^{8/3}}-\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 b^{8/3}}+\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 b^{8/3}}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2} \]
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Rubi [A]
time = 0.65, antiderivative size = 294, normalized size of antiderivative = 1.00, number of steps
used = 13, number of rules used = 10, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {1850, 1901,
1885, 1874, 31, 648, 631, 210, 642, 266} \begin {gather*} \frac {\sqrt [3]{a} \text {ArcTan}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right ) \left (a^{4/3} (-h)+\sqrt [3]{a} b e-a \sqrt [3]{b} g+b^{4/3} d\right )}{\sqrt {3} b^{8/3}}+\frac {\sqrt [3]{a} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right )}{6 b^{8/3}}-\frac {\sqrt [3]{a} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right )}{3 b^{8/3}}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2}+\frac {x (b d-a g)}{b^2}+\frac {x^2 (b e-a h)}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 210
Rule 266
Rule 631
Rule 642
Rule 648
Rule 1850
Rule 1874
Rule 1885
Rule 1901
Rubi steps
\begin {align*} \int \frac {x^2 \left (c+d x+e x^2+f x^3+g x^4+h x^5\right )}{a+b x^3} \, dx &=\frac {h x^5}{5 b}+\frac {\int \frac {x^2 \left (5 b c+5 b d x+5 (b e-a h) x^2+5 b f x^3+5 b g x^4\right )}{a+b x^3} \, dx}{5 b}\\ &=\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {\int \frac {x^2 \left (20 b^2 c+20 b (b d-a g) x+20 b (b e-a h) x^2+20 b^2 f x^3\right )}{a+b x^3} \, dx}{20 b^2}\\ &=\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {\int \frac {x^2 \left (60 b^2 (b c-a f)+60 b^2 (b d-a g) x+60 b^2 (b e-a h) x^2\right )}{a+b x^3} \, dx}{60 b^3}\\ &=\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {\int \left (60 b (b d-a g)+60 b (b e-a h) x-\frac {60 \left (a b (b d-a g)+a b (b e-a h) x-b^2 (b c-a f) x^2\right )}{a+b x^3}\right ) \, dx}{60 b^3}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}-\frac {\int \frac {a b (b d-a g)+a b (b e-a h) x-b^2 (b c-a f) x^2}{a+b x^3} \, dx}{b^3}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}-\frac {\int \frac {a b (b d-a g)+a b (b e-a h) x}{a+b x^3} \, dx}{b^3}+\frac {(b c-a f) \int \frac {x^2}{a+b x^3} \, dx}{b}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2}-\frac {\int \frac {\sqrt [3]{a} \left (2 a b^{4/3} (b d-a g)+a^{4/3} b (b e-a h)\right )+\sqrt [3]{b} \left (-a b^{4/3} (b d-a g)+a^{4/3} b (b e-a h)\right ) x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{3 a^{2/3} b^{10/3}}-\frac {\left (\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right )\right ) \int \frac {1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx}{3 b^{7/3}}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}-\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 b^{8/3}}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2}-\frac {\left (a^{2/3} \left (b^{4/3} d+\sqrt [3]{a} b e-a \sqrt [3]{b} g-a^{4/3} h\right )\right ) \int \frac {1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{2 b^{7/3}}+\frac {\left (\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right )\right ) \int \frac {-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{6 b^{8/3}}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}-\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 b^{8/3}}+\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 b^{8/3}}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2}-\frac {\left (\sqrt [3]{a} \left (b^{4/3} d+\sqrt [3]{a} b e-a \sqrt [3]{b} g-a^{4/3} h\right )\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )}{b^{8/3}}\\ &=\frac {(b d-a g) x}{b^2}+\frac {(b e-a h) x^2}{2 b^2}+\frac {f x^3}{3 b}+\frac {g x^4}{4 b}+\frac {h x^5}{5 b}+\frac {\sqrt [3]{a} \left (b^{4/3} d+\sqrt [3]{a} b e-a \sqrt [3]{b} g-a^{4/3} h\right ) \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} b^{8/3}}-\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 b^{8/3}}+\frac {\sqrt [3]{a} \left (\sqrt [3]{b} (b d-a g)-\sqrt [3]{a} (b e-a h)\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 b^{8/3}}+\frac {(b c-a f) \log \left (a+b x^3\right )}{3 b^2}\\ \end {align*}
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Mathematica [A]
time = 0.18, size = 290, normalized size = 0.99 \begin {gather*} \frac {60 b^{2/3} (b d-a g) x+30 b^{2/3} (b e-a h) x^2+20 b^{5/3} f x^3+15 b^{5/3} g x^4+12 b^{5/3} h x^5-20 \sqrt {3} \sqrt [3]{a} \left (-b^{4/3} d-\sqrt [3]{a} b e+a \sqrt [3]{b} g+a^{4/3} h\right ) \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt {3}}\right )+20 \sqrt [3]{a} \left (-b^{4/3} d+\sqrt [3]{a} b e+a \sqrt [3]{b} g-a^{4/3} h\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )+10 \sqrt [3]{a} \left (b^{4/3} d-\sqrt [3]{a} b e-a \sqrt [3]{b} g+a^{4/3} h\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )+20 b^{2/3} (b c-a f) \log \left (a+b x^3\right )}{60 b^{8/3}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.37, size = 285, normalized size = 0.97
method | result | size |
risch | \(\frac {h \,x^{5}}{5 b}+\frac {g \,x^{4}}{4 b}+\frac {f \,x^{3}}{3 b}-\frac {a h \,x^{2}}{2 b^{2}}+\frac {e \,x^{2}}{2 b}-\frac {a g x}{b^{2}}+\frac {d x}{b}+\frac {\munderset {\textit {\_R} =\RootOf \left (b \,\textit {\_Z}^{3}+a \right )}{\sum }\frac {\left (b \left (-a f +b c \right ) \textit {\_R}^{2}+a \left (a h -b e \right ) \textit {\_R} +a^{2} g -a b d \right ) \ln \left (x -\textit {\_R} \right )}{\textit {\_R}^{2}}}{3 b^{3}}\) | \(123\) |
default | \(-\frac {-\frac {1}{5} b h \,x^{5}-\frac {1}{4} b g \,x^{4}-\frac {1}{3} f \,x^{3} b +\frac {1}{2} a h \,x^{2}-\frac {1}{2} b e \,x^{2}+a g x -x b d}{b^{2}}+\frac {\left (a^{2} g -a b d \right ) \left (\frac {\ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}-\frac {\ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}+\frac {\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {2}{3}}}\right )+\left (a^{2} h -a b e \right ) \left (-\frac {\ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}+\frac {\ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}+\frac {\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )+\frac {\left (-a b f +b^{2} c \right ) \ln \left (b \,x^{3}+a \right )}{3 b}}{b^{2}}\) | \(285\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.49, size = 317, normalized size = 1.08 \begin {gather*} \frac {\sqrt {3} {\left (a^{2} h \left (\frac {a}{b}\right )^{\frac {2}{3}} - a b \left (\frac {a}{b}\right )^{\frac {2}{3}} e - a b d \left (\frac {a}{b}\right )^{\frac {1}{3}} + a^{2} g \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )} \arctan \left (\frac {\sqrt {3} {\left (2 \, x - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{3 \, a b^{2}} + \frac {12 \, b h x^{5} + 15 \, b g x^{4} + 20 \, b f x^{3} - 30 \, {\left (a h - b e\right )} x^{2} + 60 \, {\left (b d - a g\right )} x}{60 \, b^{2}} + \frac {{\left (2 \, b^{2} c \left (\frac {a}{b}\right )^{\frac {2}{3}} - 2 \, a b f \left (\frac {a}{b}\right )^{\frac {2}{3}} + a^{2} h \left (\frac {a}{b}\right )^{\frac {1}{3}} - a b \left (\frac {a}{b}\right )^{\frac {1}{3}} e + a b d - a^{2} g\right )} \log \left (x^{2} - x \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 \, b^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} + \frac {{\left (b^{2} c \left (\frac {a}{b}\right )^{\frac {2}{3}} - a b f \left (\frac {a}{b}\right )^{\frac {2}{3}} - a^{2} h \left (\frac {a}{b}\right )^{\frac {1}{3}} + a b \left (\frac {a}{b}\right )^{\frac {1}{3}} e - a b d + a^{2} g\right )} \log \left (x + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \, b^{3} \left (\frac {a}{b}\right )^{\frac {2}{3}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains complex when optimal does not.
time = 1.74, size = 14746, normalized size = 50.16 \begin {gather*} \text {too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.52, size = 333, normalized size = 1.13 \begin {gather*} \frac {{\left (b c - a f\right )} \log \left ({\left | b x^{3} + a \right |}\right )}{3 \, b^{2}} - \frac {\sqrt {3} {\left (\left (-a b^{2}\right )^{\frac {1}{3}} b^{2} d - \left (-a b^{2}\right )^{\frac {1}{3}} a b g + \left (-a b^{2}\right )^{\frac {2}{3}} a h - \left (-a b^{2}\right )^{\frac {2}{3}} b e\right )} \arctan \left (\frac {\sqrt {3} {\left (2 \, x + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{3 \, b^{4}} - \frac {{\left (\left (-a b^{2}\right )^{\frac {1}{3}} b^{2} d - \left (-a b^{2}\right )^{\frac {1}{3}} a b g - \left (-a b^{2}\right )^{\frac {2}{3}} a h + \left (-a b^{2}\right )^{\frac {2}{3}} b e\right )} \log \left (x^{2} + x \left (-\frac {a}{b}\right )^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 \, b^{4}} + \frac {12 \, b^{4} h x^{5} + 15 \, b^{4} g x^{4} + 20 \, b^{4} f x^{3} - 30 \, a b^{3} h x^{2} + 30 \, b^{4} x^{2} e + 60 \, b^{4} d x - 60 \, a b^{3} g x}{60 \, b^{5}} - \frac {{\left (a^{2} b^{9} h \left (-\frac {a}{b}\right )^{\frac {1}{3}} - a b^{10} \left (-\frac {a}{b}\right )^{\frac {1}{3}} e - a b^{10} d + a^{2} b^{9} g\right )} \left (-\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x - \left (-\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{3 \, a b^{11}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.02, size = 1170, normalized size = 3.98 \begin {gather*} x^2\,\left (\frac {e}{2\,b}-\frac {a\,h}{2\,b^2}\right )+\left (\sum _{k=1}^3\ln \left (\mathrm {root}\left (27\,b^8\,z^3+27\,a\,b^6\,f\,z^2-27\,b^7\,c\,z^2-18\,a\,b^5\,c\,f\,z+9\,a\,b^5\,d\,e\,z+9\,a^3\,b^3\,g\,h\,z-9\,a^2\,b^4\,e\,g\,z-9\,a^2\,b^4\,d\,h\,z+9\,a^2\,b^4\,f^2\,z+9\,b^6\,c^2\,z+3\,a^4\,b\,f\,g\,h-3\,a\,b^4\,c\,d\,e-3\,a^3\,b^2\,e\,f\,g-3\,a^3\,b^2\,d\,f\,h-3\,a^3\,b^2\,c\,g\,h+3\,a^2\,b^3\,d\,e\,f+3\,a^2\,b^3\,c\,e\,g+3\,a^2\,b^3\,c\,d\,h-3\,a^4\,b\,e\,h^2+3\,a\,b^4\,c^2\,f+3\,a^3\,b^2\,e^2\,h+3\,a^3\,b^2\,d\,g^2-3\,a^2\,b^3\,d^2\,g-3\,a^2\,b^3\,c\,f^2+a^3\,b^2\,f^3+a\,b^4\,d^3+a^5\,h^3-a^2\,b^3\,e^3-a^4\,b\,g^3-b^5\,c^3,z,k\right )\,\left (\frac {6\,a^2\,b^3\,f-6\,a\,b^4\,c}{b^3}+\frac {x\,\left (3\,a^2\,b^3\,g-3\,a\,b^4\,d\right )}{b^3}+\mathrm {root}\left (27\,b^8\,z^3+27\,a\,b^6\,f\,z^2-27\,b^7\,c\,z^2-18\,a\,b^5\,c\,f\,z+9\,a\,b^5\,d\,e\,z+9\,a^3\,b^3\,g\,h\,z-9\,a^2\,b^4\,e\,g\,z-9\,a^2\,b^4\,d\,h\,z+9\,a^2\,b^4\,f^2\,z+9\,b^6\,c^2\,z+3\,a^4\,b\,f\,g\,h-3\,a\,b^4\,c\,d\,e-3\,a^3\,b^2\,e\,f\,g-3\,a^3\,b^2\,d\,f\,h-3\,a^3\,b^2\,c\,g\,h+3\,a^2\,b^3\,d\,e\,f+3\,a^2\,b^3\,c\,e\,g+3\,a^2\,b^3\,c\,d\,h-3\,a^4\,b\,e\,h^2+3\,a\,b^4\,c^2\,f+3\,a^3\,b^2\,e^2\,h+3\,a^3\,b^2\,d\,g^2-3\,a^2\,b^3\,d^2\,g-3\,a^2\,b^3\,c\,f^2+a^3\,b^2\,f^3+a\,b^4\,d^3+a^5\,h^3-a^2\,b^3\,e^3-a^4\,b\,g^3-b^5\,c^3,z,k\right )\,a\,b^2\,9\right )+\frac {a\,b^3\,c^2+a^3\,b\,f^2+a^4\,g\,h-a^3\,b\,d\,h-a^3\,b\,e\,g-2\,a^2\,b^2\,c\,f+a^2\,b^2\,d\,e}{b^3}+\frac {x\,\left (a^4\,h^2+a^2\,b^2\,e^2+a\,b^3\,c\,d-2\,a^3\,b\,e\,h+a^3\,b\,f\,g-a^2\,b^2\,c\,g-a^2\,b^2\,d\,f\right )}{b^3}\right )\,\mathrm {root}\left (27\,b^8\,z^3+27\,a\,b^6\,f\,z^2-27\,b^7\,c\,z^2-18\,a\,b^5\,c\,f\,z+9\,a\,b^5\,d\,e\,z+9\,a^3\,b^3\,g\,h\,z-9\,a^2\,b^4\,e\,g\,z-9\,a^2\,b^4\,d\,h\,z+9\,a^2\,b^4\,f^2\,z+9\,b^6\,c^2\,z+3\,a^4\,b\,f\,g\,h-3\,a\,b^4\,c\,d\,e-3\,a^3\,b^2\,e\,f\,g-3\,a^3\,b^2\,d\,f\,h-3\,a^3\,b^2\,c\,g\,h+3\,a^2\,b^3\,d\,e\,f+3\,a^2\,b^3\,c\,e\,g+3\,a^2\,b^3\,c\,d\,h-3\,a^4\,b\,e\,h^2+3\,a\,b^4\,c^2\,f+3\,a^3\,b^2\,e^2\,h+3\,a^3\,b^2\,d\,g^2-3\,a^2\,b^3\,d^2\,g-3\,a^2\,b^3\,c\,f^2+a^3\,b^2\,f^3+a\,b^4\,d^3+a^5\,h^3-a^2\,b^3\,e^3-a^4\,b\,g^3-b^5\,c^3,z,k\right )\right )+x\,\left (\frac {d}{b}-\frac {a\,g}{b^2}\right )+\frac {f\,x^3}{3\,b}+\frac {g\,x^4}{4\,b}+\frac {h\,x^5}{5\,b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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